Wednesday, June 4, 2025

Mathethically proof entanglement

To mathematically prove quantum entanglement, we demonstrate that a given quantum state cannot be expressed as a tensor product of individual subsystem states. We'll use the Bell state \(|\Phi^+\rangle = \frac{1}{\sqrt{2}} (|00\rangle + |11\rangle)\) as an example, showing it violates the separability condition. We include two methods: (1) direct decomposition and (2) reduced density matrix analysis.


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Method 1: Proof by Contradiction (Direct Decomposition)

Assume \(|\Phi^+\rangle\) is separable, meaning it can be written as a tensor product:  

\[

|\Phi^+\rangle = (a|0\rangle + b|1\rangle) \otimes (c|0\rangle + d|1\rangle),

\]  

where \(a, b, c, d \in \mathbb{C}\) and normalization requires \(|a|^2 + |b|^2 = 1\), \(|c|^2 + |d|^2 = 1\).  


Expanding the tensor product:  

\[

(a|0\rangle + b|1\rangle) \otimes (c|0\rangle + d|1\rangle) = ac|00\rangle + ad|01\rangle + bc|10\rangle + bd|11\rangle.

\]  


Equate this to \(|\Phi^+\rangle\):  

\[

ac|00\rangle + ad|01\rangle + bc|10\rangle + bd|11\rangle = \frac{1}{\sqrt{2}}|00\rangle + 0|01\rangle + 0|10\rangle + \frac{1}{\sqrt{2}}|11\rangle.

\]  


This yields the system:  

1. \(ac = \frac{1}{\sqrt{2}}\),  

2. \(ad = 0\),  

3. \(bc = 0\),  

4. \(bd = \frac{1}{\sqrt{2}}\).  


Solving the system:

- From (2): \(ad = 0\) \(\implies\) \(a = 0\) or \(d = 0\).  

- From (3): \(bc = 0\) \(\implies\) \(b = 0\) or \(c = 0\).  


Case 1: \(a = 0\)  

- From (1): \(0 \cdot c = 0 = \frac{1}{\sqrt{2}}\) → Contradiction.  


Case 2:\(d = 0\)  

- From (4): \(b \cdot 0 = 0 = \frac{1}{\sqrt{2}}\) → Contradiction.  


Conclusion:The system has no solution. Thus, \(|\Phi^+\rangle\) cannot be written as a tensor product → entangled.


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Method 2: Reduced Density Matrix Analysis

For a separable state, the reduced density matrix of a subsystem is pure. If mixed, the state is entangled.  


Step 1: Full density matrix \(\rho\)

\[

\rho = |\Phi^+\rangle \langle \Phi^+| = \frac{1}{2} \left( |00\rangle\langle 00| + |00\rangle\langle 11| + |11\rangle\langle 00| + |11\rangle\langle 11| \right).

\]


Step 2: Compute reduced density matrix for subsystem A (first qubit)

Trace out subsystem B:  

\[

\rho_A = \text{Tr}_B(\rho) = \sum_{k=0,1} \langle k_B | \rho | k_B \rangle.

\]


- Term for \(k=0\): 

  \[

  \langle 0_B | \rho | 0_B \rangle = \frac{1}{2} \langle 0_B| \left( |00\rangle\langle 00| + |00\rangle\langle 11| + |11\rangle\langle 00| + |11\rangle\langle 11| \right) |0_B\rangle.

  \]  

  Using \(\langle 0_B|00\rangle = |0_A\rangle\), \(\langle 0_B|11\rangle = 0\):  

  \[

  = \frac{1}{2} \left( |0_A\rangle\langle 0_A| + 0 + 0 + 0 \right) = \frac{1}{2} |0_A\rangle\langle 0_A|.

  \]


- Term for \(k=1\):

  \[

  \langle 1_B | \rho | 1_B \rangle = \frac{1}{2} \langle 1_B| \left( \cdots \right) |1_B\rangle.

  \]  

  Using \(\langle 1_B|00\rangle = 0\), \(\langle 1_B|11\rangle = |1_A\rangle\):  

  \[

  = \frac{1}{2} \left( 0 + 0 + 0 + |1_A\rangle\langle 1_A| \right) = \frac{1}{2} |1_A\rangle\langle 1_A|.

  \]


Step 3: Combine terms  

\[

\rho_A = \frac{1}{2} |0_A\rangle\langle 0_A| + \frac{1}{2} |1_A\rangle\langle 1_A| = \frac{1}{2} \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix}.

\]  

This is the maximally mixed state with eigenvalues \(\frac{1}{2}, \frac{1}{2}\).  


Conclusion:\(\rho_A\) is mixed → entangled.


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Key Points

- Entanglement criterion: A state is entangled if it is not separable (i.e., cannot be written as \(\bigotimes_i |\psi_i\rangle\)).

- Bell state violation:The Bell state \(|\Phi^+\rangle\) violates separability, proving entanglement.

- Generalization: For any bipartite pure state, entanglement occurs iff the Schmidt rank > 1. Here, the Schmidt decomposition is \(|\Phi^+\rangle = \frac{1}{\sqrt{2}}|0_A0_B\rangle + \frac{1}{\sqrt{2}}|1_A1_B\rangle\) (Schmidt rank 2 → entangled).


This proof confirms quantum entanglement through algebraic contradiction and mixed-state subsystems.

Explanation 

Here's a step-by-step explanation of quantum entanglement using the Bell state example, translated into everyday language without formulas:


  The Core Idea of Entanglement

Imagine two coins that are magically linked. When you flip them:

- They always land showing the same side (both heads or both tails)

- But until you look, they exist in a ghostly "both possibilities at once" state

- The moment you see one coin, the other instantly "chooses" its state


This mysterious connection that defies normal physics is entanglement.


---


 Method 1 Explained: The Impossible Puzzle (Direct Decomposition)

The Setup:

1. We have our quantum "coins" (qubits) in state:  

   "50% chance both heads | 50% chance both tails"


2. We try to describe them as independent objects(like normal coins):  

   - Coin A = (x% heads + y% tails)  

   - Coin B = (p% heads + q% tails)  


The Contradiction:

- For our entangled state:  

  Both heads must have 50% probability  

  Both tails must have 50% probability  

  ❌ Mismatched results (A-heads+B-tails or A-tails+B-heads) must have 0% probability  


- But if they're independent:  

  - Probability of both heads = (A-heads%) × (B-heads%)  

  - Probability of both tails = (A-tails%) × (B-tails%)  


The Impossible Math.

- To get 50% for both heads:  

  (A-heads%) × (B-heads%) = 50%  

- To get 0% for mismatches:  

  Either A never shows heads OR B never shows tails...  

  ...but then both tails would be (A-tails%) × (B-tails%) = ?  


The Conclusion:

➡️ No combination works!

➡️ The coins can't be independent - their fates are mathematically linked.  

➡️ This proves entanglement isn't just hidden coordination - it's fundamental connection.


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🪙 Method 2 Explained: The Phantom Coin (Reduced Density Matrix)

The Experiment:

1. We entangle two coins and mail one to Paris, one to Tokyo.  

2. In Paris, scientists examine only their local coin.


What Paris Sees:

- Their coin appears completely random:  

  - 50% chance heads 🪙  

  - 50% chance tails 🪙  

  - Like flipping a normal coin*


The Quantum Twist:

- If the coins were truly independent:  

  - Paris's randomness would be "real"  

  - Tokyo's coin would be unrelated  


- But in entanglement:  

  - The moment Paris looks...  

  - Their coin "collapses" to heads/tails  

  - Tokyo's coin instantly collapses to match!  


Why This Proves Entanglement:

- Paris sees maximum randomness (50/50)  

- Yet this randomness disappears when comparing results with Tokyo  

- The randomness was actually shared quantum information - not true independence  


The Conclusion:  

➡️ Individual coins show perfect randomness  

➡️ But together they show perfect correlation  

➡️ This proves they share a single quantum state across distance  


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 💡 Key Intuitive Takeaways

1. The whole > sum of parts:  

   Entangled particles are like a single "quantum object" split across space - you can't describe one without the other.


2. Spooky action at distance:  

   Changing one particle instantly affects its partner, no matter how far apart (verified by experiments).


3. Not hidden variables:  

   Our math proves this isn't just pre-agreed coordination (like identical twins) - it's deeper quantum connection.


4. Usefulness:  

   This "quantum link" enables:  

   - Ultra-secure communication (quantum cryptography)  

   - Computers solving impossible problems (quantum computing)  

   - Teleporting quantum information


> Entanglement isn't weird - it's quantum reality. We're the weird ones for expecting particles to behave like billiard balls."  

> - Adapted from Niels Bohr




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